Question

find simple interest on 20000 Rs for 5 years at 4% p.a​

Answer 1

Answer:

hope it can help you

thank u

Answer 2

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Given:}}}}}}}\end{gathered}$

$\dashrightarrow\sf{Principle = 20000}$

$\dashrightarrow\sf{Rate = 10 \%}$

$\dashrightarrow{\sf{Time = 4 \: years}}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{blue}{To Find:}}}}}}}\end{gathered}$

Simple Interest

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{darkblue}{Using Formula:}}}}}}}\end{gathered}$

$\dag\underline{\boxed{\sf{S.I = \bigg\{\dfrac{P \times R \times T}{100}\bigg\}}}}</p><p>\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{blue}{Solution:}}}}}}}\end{gathered}$

$\quad { \implies{\sf{S.I = \bf\bigg(\dfrac{P \times R \times T}{100}\bigg)}}}$

Substitute the values..

$\quad {\implies{\sf{S.I = \bf\bigg(\dfrac{20000 \times 10 \times 4}{100}\bigg)}}}$

$\quad { \implies{\sf{S.I = \bf\bigg(\dfrac{200{\cancel{00}} \times 10 \times 4}{\cancel{100}}\bigg)}}}$

$\quad { \implies{\sf{S.I = \bf{200 \times 10 \times 4}}}}$

$\quad {\implies{\sf{S.I = \bf{8000}}}}$

$\begin{gathered} \dag{\overline{\underline{\boxed{\textsf{\textbf{\color{red}{S.I = Rs.8000}}}}}}}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{pink}{Learn More:}}}}}}}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \bigstar \underline \purple{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc} {\sf{Amount = Principle + Interest}} \\ \\ \sf{ P=Amount - Interest }\\ \\ \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}$