Question

Find simple interest on 8000 for 9 months at 50/3p.a

Answer 1

we know that SI=PNR/100

P=8000

N=3/4

R=50/3

putting the values in the formula

we get

SI=8000×3/4×50/3×1/100

=100000/100

=Rs1000

Please mark it as brainliest.

Answer 2

Answer:

$\red { Simple Interest} \green{ = Rs \:1000}$

Step-by-step explanation:

$Principal (P) = Rs \: 8000$

$Time (T) = 9 \: months \\= \frac{9}{12} \: years \\= \frac{3}{4} \: years$

$Rate \: of \: interest (R) = \frac{50}{3} \:p.a$

$\boxed { \pink { Simple Interest = \frac{PTR}{100} }}$

$= \frac{ 8000 \times \frac{3}{4} \times \frac{50}{3}}{100} \\= \frac{8000 \times 3 \times 50}{100\times 4 \times 3 }\\= Rs \:1000$

Therefore.,

$\red { Simple Interest} \green{ = Rs \:1000}$

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