Question

find simple interest when principal=5000rs ,rate=9%p.a. and time =2 years

Answer 1

Principal=₹5000
Time=2years
Rate%=9%
Simple Interest= (P×R×T)/100
= (5000×9×2)/100
=₹900.
Hope it helps u.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=900\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 2\:years} \\ \\ : \implies \text{Principal(p) = 5000\:rupees} \\ \\ : \implies \text{Rate(r) = 9\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{5000 \times 9 \times2 }{100} \\ \\ : \implies S.I = \frac{5000\times18 }{100} \\ \\ \green{ : \implies \text{S.I= 900\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =900\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$