Question

Find simple interest when principal is 12000 rate is 18•5% and time is 2 •5%

Answer 1

555000100

Step-by-step explanation:

principal = 12000

Rate = 18.5

Time = 2.5

simple interest = P TR/ 100

= 12000 × 18.5× 2.5

1. = 555000 /100 ANSWER = 555000100

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=5550\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 2.5\: years} \\ \\ : \implies \text{Principal(p) = 12000\:rupees} \\ \\ : \implies \text{Rate(r) = 18.5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{12000 \times 18.5 \times 2.5}{100} \\ \\ : \implies S.I = \frac{12000\times 46.25 }{100} \\ \\ \green{ : \implies \text{S.I= 5550\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =5550\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$