Question

find simple interest where principal= ₹8000, rate = 5% , and time = 2 years​

Answer 1

Answer:

s.i =prt/100

8000*5*2/100

=₹800

Hope it help...

Answer 2

Answer:

$\large\boxed{\sf{Rs.\;800}}$

Step-by-step explanation:

Principal, p = ₹ 8000

Rate of interest , r = 5% per annum

Time , t = 2 years

Let, Simple Interest = S.I

We know that,

$\large \boxed{ \red{S.I= \frac{p \times r \times t}{100} }}$

Putting the respective values, we get,

$= > S.I = \frac{8000 \times 5 \times 2}{100} \\ \\ = > S.I = 80 \times 10 \\ \\ = > S.I = 800$

Hence, Simple Interest is ₹ 800