find sin^-1 2/3 + sin^-1 √5/3
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Answer:
sin^-1 2/3 = a , sin^-1 √5/3 = b
(we convert sin^-1 to cos^-1
and then use cos(a-b))
Let sin^-1 2/3 = a
sin^-1 a = 2/3
cos a=√1-sin^2a
= √1-(2/3)^2
= √1-4/9 = -5/9
and solve 2nd cos like this
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