Question

find sin×/2 if tanx=-4/3 and x lies in 4th quadrant

Answer 1

$\tan(x) = - \frac{4}{3}$
$= > \sin(x) = - \frac{4}{ \sqrt{ {3}^{2} + {4}^{2} } }$
$= > \sin(x) = - \frac{4}{5}$
sin (x ) is negative as x lies in 4th quadrant.