Question

find sin(90-x).cosec(90-x)​

Answer 1

Step-by-step explanation:

To Find :-

Value of :-

sin(90° - x).csc(90° - x)

Solution :-

Method 1 :-

sin(90° - x).csc(90° - x)

= sin(90° - x). 1/sin(90° - x)

[ cscA = 1/sinA]

= 1

Method 1 :-

sin(90° - x).csc(90° - x)

= cosx.secx

[ sin(90° - A) = cosA , csc(90° - A) = secA ]

= cosx. 1/cosx

[ secA = 1/cosA ]

= 1

Formula Used :-

1) cscA = 1/sinA

2) sin(90° - A) = cosA

3) csc(90° - A) = secA

4) secA = 1/cosA