Find sin(90° - 0), cos 0 and tan 0. if PR=15 and RQ=12 and angleQ=90°
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Let the common multiple be k. ∴ PQ = 5k and PR = 13k Find QR by using Pythagoras theorem. PR2 = PQ2 + QR2 … [Pythagoras theorem] ∴ (13k)2 = (5k)2 + QR2 ∴ 169k2 = 25k2 + QR2 ∴ QR2 = 169k2 – 25k2 = 144k2 ∴ QR = √(144k2) . . . [Taking square root of both sides] = 12k Read more on Sarthaks.com - https://www.sarthaks.com/850966/in-right-angled-pqr-q-90-r-and-if-sin-5-13-then-find-cos-and-tan?show=850971#a850971
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