find sin(a+b),given that sin a=3/5, cosb =5/13, a and b are in 1 quadrant
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sin(a+b)
sinacosb+cosasinb
sina=3/5
cosa=√1-sin²a
cosa=4/5
cosb=5/13
sinb=√1-cos²b
sinb=12/13
so
sin(a+b)
3/5*5/13+4/5*12/13
15/65+48/65
63/65
I hope it is suitable answer
sinacosb+cosasinb
sina=3/5
cosa=√1-sin²a
cosa=4/5
cosb=5/13
sinb=√1-cos²b
sinb=12/13
so
sin(a+b)
3/5*5/13+4/5*12/13
15/65+48/65
63/65
I hope it is suitable answer
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0
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