Find sin a + Cos a if sin a minus Cos is equal to root 3 minus 1 by 2
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sin A - cos A = √3-1/2
whole squaring both sides
1-2sinAcosA = 4-2√3/4
2sinAcosA = √3/2
sinAcosA = √3/4
(sin A +cos A)^2 = 1+2sinAcosA
(sinA +cosA)² = 2+√3/2
sinA +cos A = √{(2+√3)/2}
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Answered by
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sina-cosa=√3-1[1/2]
(sina-cosa)(Sina+cosa)=sin²a-cos²a=1
√3-1(1/2)(Sina+cosa)=1
Sina+cosa=2(1/√3-1)
Answer=2(1/√3-1)
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