Question

find sin x, cos x ,cot x,sec x,coses if tan x=40/9

Answer 1

sin x = 40
cos x = 9
cot x = 9/40
sec x = 1/9
cosec x = 1/40

Answer 2

Here tan x=40/9 We know that Tan x=p/b=40/9 So p=40 unit and b=9 unit Now using pathogirus theorm H^2 =p^2+b^2 H^2=40^2+9^2=1600+81=1681 Or h= root under 1681 H= 41 unit sin x=p/h=40/41 cos x= b/h=9/41 Cot x=b/p=9/40 sec x=h/b=41/9 Cosesx= h/p=41/40