Find sinA and cosA, if angle B is 90°,AB=24cm and BC=7cm
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✰ Given:
AB = 24cm
BC = 7cm
∠B = 90°
✰ To find:
Sin A = ?
Cos A = ?
✰ Solution :
In right angled ∆ ABC,
According to Pythagoras Theorem,
→ AC² = AB² + BC²
→ AC² = (24)² + (7)²
→ AC² = 576 + 49
→ AC² = 625
Taking Square root on both the sides,
We get,
∴ AC = 25
Now,
Sin A = Opposite side of A / Hypotenuse
= BC / AC
= 7 / 25
Cos A = Adjacent side of A/ Hypotenuse
= AB / AC
= 24 / 25
✰ Answer :
Sin A = 7/25
Cos A = 24/25
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