Question

Find SinA,CosA and TanA when SinA/2=3/5​

Answer 1

Sin A =P/H

3/5=P/H

B^2=H^2-P^2

B^2=5^2-3^2

B^2=25-9

B=4

TanA=P/B

TanA=3/4

Answer 2

Answer:

sin 37=3/5 cos 37=4/5

a/2=37 degree so

sina =24/25

cos a =7/25

tan a=24/7