Question

find sinA if 3cosA+4sinA = 4​

Answer 1

Step-by-step explanation:

3cosA+4sinA=4

3/sinA+4sinA=4

3+4sin^2A/sinA=4

3+4sin^2A=4SinA

3=4sinA-4sin^2A

3=4sinA(1-sinA)

3/4sinA=1-sinA

sinA=1-3/4sinA

sinA=4sinA-3/4sinA