Question

find sinA such that 3cosA+4sinA=4​

Answer 1

Answer:

Step-by-step explanation:

sinA= 4-3cosA/4

Answer 2

Answer:

Hence, the value of $sinA=\frac{4-3cosA}{4}$.

Step-by-step explanation:

Consider the provided equation.

$3cos A+4sin A=4$

We need to solve the equation for sin A.

Subtract 3 cosA from both sides.

$3cosA-3cosA+4sinA=4-3cosA$

$4sinA=4-3cosA$

Divide both sides by 4.

$\frac{4sinA}{4}=\frac{4-3cosA}{4}$

$sinA=\frac{4-3cosA}{4}$

Hence, the value of $sinA=\frac{4-3cosA}{4}$.