find single discount equivalent to a discount series of 20% 10% and 5%
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Let MP be ₹100 ( you take any other no. or can take x)
price after first discount = 100(1 - 20/100) = ₹80
price after second discount = 80(1- 10/100)=
₹ 72
price after third discount = ₹72(1 -5/100) = ₹68.4
( so now we have to find a discount which will be (100 - 68.4 ) = ₹ 31.6)
Let discount be d%
d/100 × 100 = 31.6 = 31.6%
Ans 31.6%
price after first discount = 100(1 - 20/100) = ₹80
price after second discount = 80(1- 10/100)=
₹ 72
price after third discount = ₹72(1 -5/100) = ₹68.4
( so now we have to find a discount which will be (100 - 68.4 ) = ₹ 31.6)
Let discount be d%
d/100 × 100 = 31.6 = 31.6%
Ans 31.6%
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