find sinø such that 3cosø+4sinø=4
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Answer:
sin theta = 1 or 7/25
Step-by-step explanation:
i am using A in place of theta
3cosA + 4sinA = 4
3cosA = 4 - 4sinA
3cosA = 4(1 - sinA)
squaring both side
9cos^2A = 16(1 - sinA)^2
9(1 - sin^2A) = 16(1 - sinA)^2
9(1 - sinA)(1 + sinA) - 16 ((1 - sinA)^2 = 0
(1 - sinA) * {9(1+sinA) - 16(1 - sinA)} = 0
this means either
1 - sinA = 0 which gives sinA = 1
or, 9(1+sinA)-16(1-sinA) = 0
9 + 9sinA - 16 + 16sinA = 0
25 sinA = 7
sinA = 7/25
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