Question

Find sinx in form of secx....

Answer 1

Find sinx in form of secx,

Good question,

Here is your perfect answer!

sin²x + cos²x = 1

=) sin²x = 1 - cos²x

=) sin²x = 1- (1/sec²x)

=) sin²x = (sec²x-1) /sec²x

=) sinx = under root [(sec²x-1)]/secx

Or under root[(secx+1)(secx-1)]/ secx.

Answer 2

$\huge \bf{ \red{ANSWER}}$

$\bf{QUESTION }$
Find sinx in form of secx....

$\bf{step \: by \: step \: explanation}$
sec x= 1/cosx

cos^2x+sin^2x=1

hence

cos^2x=1-sin^2x



hence

sec x= 1/1-sin^2x

1-sin^2x=secx

-sin^2x=secx-1

sinx=_/secx-1

Hence solved

THANKS