Question

Find six angles for which sin 0 =√3/2

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Answer 1

Step-by-step explanation:

sin A = sqrt(3)/2

cos A = 1/2

Proof: cos^2 A + sin^2 A = (1/2)^2 + (sqrt(3)/2)^2 = 1/4 + 3/4 = 1. Check.

So, tan A = sin A / cos A = sqrt(3)

cot A = 1 / tan A = 1/sqrt(3)

sec A = 1 / cos A = 2

csc A = 1 / sin A = 2 / sqrt(3)

Answer 2

Step-by-step explanation:

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