find six angles for which sin theta= -√3/2
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Sin Q = √3/2
Q = Sin^(-1) [√3/2]
= 60 °
Cos 60 = 1/2
Tan 60 = √3
Cosec 60 = 2/√3
Sec 60 = 2
Cot 60 = 1 /√3
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