Question

Find six consecutive numbers whose sum is 141.​

Answer 1

Step-by-step explanation:

Since their sum is 141 we write the equation: x+x+2+x+4=141, 3x+6=141, 3x=135, x=45. The first ood number is 45, the second 45+2=47 and the third 47+2=49.

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Answer 2

six consecutive numbers are = 21,22,23,24,25,26

Step-by-step explanation:

let the consecutive numbers be = x+(x+1) + (x+2) + (x+3) + (x+4) + (x+5)

sum if the six consecutive no is = 141

x+(x+1) + (x+2) + (x+3) + (x+4) + (x+5) =141

6x + 15 = 141

6x= 141-15 = 126

x= 126 ÷ 6

x= 21

First number = x = 21

second number = x+1 = 21+1 = 22

third number= (x+2) = 21+2= 23

fourth number = (x+3) = 21+3 = 24

fifth number = (x+4) = 21+4 = 25

sixth number= (x+5) = 21+5 = 26

21+22+23+24+25+26 = 141

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