Question

Find six rational nunbers between 3 and 4.

Answer 1

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• 1st number, x = 3
• 2nd number, y =4
• find number, n = 6

Now,

$d = \frac{y - x}{n + 1} = > \frac{4 - 3}{6 + 1} = \frac{1}{7}$

$\star \: x + d = 3 + \frac{1}{7} = \frac{21 + 1}{7} = \frac{22}{7}$

$\star \: x + 2d = 3 + \frac{2}{7} = \frac{21 + 2}{7} = \frac{23}{7}$

$\star \: x + 3d = 3 + \frac{3}{7} = \frac{21 + 3}{7} = \frac{24}{7}$

$\star \: x + 4d = 3 + \frac{4}{7} = \frac{21 + 4}{7} = \frac{25}{7}$

$\star \: x + 5d = 3 + \frac{5}{7} = \frac{21 + 5}{7} = \frac{26}{7}$

$\star \: x + 6d = 3 + \frac{6}{7} = \frac{21 + 6}{7} = \frac{27}{7}$

Hence, Six rational number between 3 and 4 are 22/7,23/7,24/7,25/7,26/7 and 27/7.

Answer 2

Answer:

$\mathcal \huge\bf \green{HOPE \: IT \: HELPS \: YOU}$