Question

find six solutions for the following linear equations in two variables 12x-4y=20​

Answer 1

Answer:

Subtract the equation (1) and (2)

12x+4y=20 ----- (1)

4x−4y=−20----- (2)

______________

16x=0

x=

16

0

=0

Put the value of x in equation (1), we get

12x+4y=20

12(0)+4y=20

4y=20

y=

4

20

=5

Therefore the solution is (0, 5)

Answer 2

Step-by-step explanation:

I hope it's helpful for you