Question

Find slope of line perpendicular to the line 2x + 5y - 3 =0​

Answer 1

Answer:

The slope of a line perpendicular to 2x+5y-3=0 would be 5%2F2; and the y-intercept of 2x+3y+6=0 would be...

3y=-2x-6

y=-2x/3-2

 

.... is 2.

Answer 2

The slope of the line is  $m=-\frac{2}{5}$

Explanation:

Given:

Perpendicular line 2x+5y-3=0

To find:

The slope of the line

General form:

The equation of a straight line is ax+by+c=0

The equation can be written as $y=-\frac{a}{b}x-\frac{c}{b}$

The slope- intercept form is y=mx+c

Slope, m = $-\frac{a}{b}$

Method 1:

==> The equation of the line is 2x+5y-3=0

==> Change the equation as Slope-Intercept form y=mx+c

==> 2x+5y-3=0

==> 2x+5y=3

==> 5y=3-2x

==> 5y = -2x+3

==> $y= -\frac{2}{5}x +\frac{3}{5}$ ==> 1

==> y = mx+c ==>2

==> Comparing equation 1 and 2

==> $m= -\frac{2}{5}$

Method2:

$m=-\frac{coefficientof x}{Coefficient of y}$

==> The equation is 2x+5y-3=0

==> Coefficient of x is 2

==> Coefficient of y is  5

==> $m=-\frac{2}{5}$