Question

find slopes x-intercept and y- intercept of the line 2x+3y-11=0

Answer 1

Answer:

Step-by-step explanation:

Line parallel to 2x+3y+11=0 is

2x+3y+k=0

y-intercept when x=0 is

3y+k =0 i. e. y=-k/3

x-intercept when y=0 is

2x+k=0 i. e. x=-k/2

Since the sum of intercepts is 15

Hence(-k/3)+(-k/2)=15

i.e. -5k/6=15

hence k=-18

Equation of required line is

2x+3y-18=0

Answer 2

2x+3y-11=0
Convert in the form y=mx+c
3y= - 2x+11
y= - 2/3x+11/3
Compare this to y=mx+c
Slope=m= - 2/3
Y-intercept =c =11/3

Hope it helped you