Question

Find smallest 4 digit number which when divided by 24 36 48 leaves remainder 5 every time

Answer 1

Take the LCM (Divisors)

Least possible number = LCM (Divisors) + Remainder

And any other such possible number will be in format “m.LCM(Divisors) +Remainder”

3. Now , check for what least value of m , required number will be a 4- digit number