Find smallest four digit no. Which is exactly divisible by 18,24,32
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0
Answer:
after taking the LCM multipling the numbers 2*2*2*2*2*3*3=288
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Answered by
1
Answer:
1152
Step-by-step explanation:
First find the LCM of 18, 24 and 32:
18 = 2 x 3 x 3
24 = 2 x 2 x 2 x 3
32 = 2 x 2 x 2 x 2 x 2
LCM = 288
Now find the smallest four digit number that is exactly divisible by 288
so 288*4 = 1152
Since 288 is divisible by 18, 24 and 32, 1152 is also divisible by all these numbers.
so the smallest 4 digit number is 1152
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