Find smallest no which leaves remainder 8 and 12 when divided by 28 and 32
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To find the smallest number , follow these steps :-
1) Subtract the remainders from the given numbers:
28-8 = 20
32 -12 = 20
Both of them give 20
2) Find the LCM of 28 and 32
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
LCM = 2 × 2 × 2 × 2 × 2 × 7 = 224
3) Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32 = LCM -20 = 224 - 20 = 204
204 is the answer !!!
1) Subtract the remainders from the given numbers:
28-8 = 20
32 -12 = 20
Both of them give 20
2) Find the LCM of 28 and 32
28 = 2 × 2 × 7
32 = 2 × 2 × 2 × 2 × 2
LCM = 2 × 2 × 2 × 2 × 2 × 7 = 224
3) Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32 = LCM -20 = 224 - 20 = 204
204 is the answer !!!
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