Math, asked by janjuapuneetkaur, 3 months ago

find smallest number by which 243 be multiplied to obtain perfect cube​

Answers

Answered by sumerbhambhu1980
0

Answer:

answer = 9

Step-by-step explanation:

divide 243 by prime factorisation method as explained in above picture and make pair of three numbers and if numbers are left after making pair multiply them. thank you

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Answered by sonylivhd
1

Step-by-step explanation:

By Prime factorisation

243 = 3 × 3 × 3 × 3 × 3 [Grouping the factors in triplets]

The prime factore 3 does not appear in a group of three

Therefore, 243 is not a prefect cube. To make it a cube, we need one more 3

In that case, multiplying 3 on both sides

243 × 3 = 3 × 3 × 3 × 3 × 3 × 3

3 3 m n m + n

3 × 3 [ a × a = a ]

3 m m m

9 [ a × b = ( a × b) ]

729 is a prefect cube of 9

Hope it helps you

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