find smallest number by which 243 be multiplied to obtain perfect cube
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Answer:
answer = 9
Step-by-step explanation:
divide 243 by prime factorisation method as explained in above picture and make pair of three numbers and if numbers are left after making pair multiply them. thank you
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Step-by-step explanation:
By Prime factorisation
243 = 3 × 3 × 3 × 3 × 3 [Grouping the factors in triplets]
The prime factore 3 does not appear in a group of three
Therefore, 243 is not a prefect cube. To make it a cube, we need one more 3
In that case, multiplying 3 on both sides
243 × 3 = 3 × 3 × 3 × 3 × 3 × 3
3 3 m n m + n
3 × 3 [ a × a = a ]
3 m m m
9 [ a × b = ( a × b) ]
729 is a prefect cube of 9
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