Question

find smallest number which leaves the remainder
2. when divided by
by 16,24 and 30​

Answer 1

Answer:

so number=240+2=242

Step-by-step explanation:

prime factors of 16,24,30 are

16=2*2*2*2

24=2*2*2*3

30=2*3*5

LCM(16,24,30)=2^4*3*5

=16*15=240

Remainder in three case is 2

so number=240+2=242