find (sn=2+22+222+..........n terms
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Step-by-step explanation:
2+22+222+2222+........ n terms
2(1+11+111+1111+....... n terms)
2(9+99+999+..........n terms)
9
2(10-1+10²-1+10³-1+10⁴-1+.......n terms)
9
2(10+10²+10³+.....nterms-1-1-1....n terms)
9
2(10+10²+10³+.....nterms-n)
9
2(10(10^n-1)-n)
9. (9)
2[10(10^n-1)-9n]
9[9]
2 (10(10^n-1)-9n)
81
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