Question

Find Sn for √2, √8, √18 … …​

Answer 1

Given ,,,

a = √2

d = √2

Sn = n [ 2×√2+(n–1) ×√2]

2

= n [2√2 +√2n–√2]

2

= n [√2+√2n]

= n ×√2 (1+n) {cancelling 2 and √2}

2

= n (1+n)

√2

= n²+n

√2

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