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Given f(x) = kx^2 + 3x + k.
Given one of the zero of f(x) is 2.
Hence f(2) = 0.
f(2) = k(2)^2 + 3(2) + k = 0
= 4k + 6 + k = 0
= 5k + 6 = 0
5k = -6
k = -6/5.
Therefore the value of k = -6/5.
Hope this helps!
Given one of the zero of f(x) is 2.
Hence f(2) = 0.
f(2) = k(2)^2 + 3(2) + k = 0
= 4k + 6 + k = 0
= 5k + 6 = 0
5k = -6
k = -6/5.
Therefore the value of k = -6/5.
Hope this helps!
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Hi,
Please see the attached file!
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Please see the attached file!
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