Find solution of x+3=5 using trial and error method.
Answers
X=2
Step-by-step explanation:
ABOVE STEP IS CORRECT BUT THE VALUE OF X IS 2
Given,
Equation: x + 3 = 5.
To find,
Solution using trial and error method.
Solution,
The trial and error method is one in which the different values of the variable are substituted one by one in the equation, and then it is compared if the LHS equals RHS or not.
Here, the given equation is,
x + 3 = 5 ...(1)
Means,
LHS = x + 3,
RHS = 5.
1. First, let's try by substituting x = 0 in eq. (1), then,
LHS = x + 3
= 0 + 3
= 3
Since RHS = 5
⇒ LHS ≠ RHS.
Thus, x = 0 is not a solution to the given equation.
2. Now, let's substitute x = 1 in eq. (1), then,
LHS = x + 3
= 1 + 3
= 4
Again, LHS ≠ RHS.
Thus, x = 1 is not a solution to the given equation.
3. Now, let x = 2, then, putting in eq. (1), we get,
LHS = x + 3
= 2 + 3
= 5
We can see that when x = 2, we get,
LHS = 5 = RHS
⇒ LHS = RHS
Thus, x = 2 is a solution to the given equation.
Therefore, using the trial and error method, the solution of the given equation x + 3 = 5, is x = 2.