Question

Find solution set of 2x+3/x-2 <1/2​

Answer 1

Answer:

x+321

Step-by-step explanation:

!@)₹(9jwb2764992?+81977390197773)(+92878299292(2+28827272992(2829929292(2+2937

Answer 2

Answer:

Step-by-step explanation:

Let's solve your inequality step-by-step.

2x+

3

x

−2<

1

2

2x2−2x+3

x

<

1

2

Let's find the critical points of the inequality.

2x2−2x+3

x

=

1

2

2x2−2x+3=

1

2

x(Multiply both sides by x)

2x2−2x+3−

1

2

x=

1

2

x−

1

2

x(Subtract 1/2x from both sides)

2x2+

−5

2

x+3=0

For this equation: a=2, b=-2.5, c=3

2x2+−2.5x+3=0

x=

−b±√b2−4ac

2a

(Use quadratic formula with a=2, b=-2.5, c=3)

x=

−(−2.5)±√(−2.5)2−4(2)(3)

2(2)

x=

2.5±√−17.75

4

Critical points:

x=0(Makes left denominator equal to 0)

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x<0(Works in original inequality)

x>0(Doesn't work in original inequality)

Answer:

X=<0