Math, asked by mail2ravikumar87, 10 months ago

find solutions of √7√7√7√7root 7 root 7 root 7 root 7 continuously ​

Answers

Answered by sanaaaa123
1

Answer:

let n be the no. of times you are multiplying √7

if n is even then 7 raised to n divide by 2 is the ans

and if n is odd then 7 raised to n-1 × √7 is the ans

if it helps pls mark brainliest

Answered by Mudit1419J
0

Answer:

as root 7 is coming continuously so put a bar on root 7 in way like our do in Normal numbers like 8 a coming unlimited times bar 8

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