find solutions of √7√7√7√7root 7 root 7 root 7 root 7 continuously
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Answered by
1
Answer:
let n be the no. of times you are multiplying √7
if n is even then 7 raised to n divide by 2 is the ans
and if n is odd then 7 raised to n-1 × √7 is the ans
if it helps pls mark brainliest
Answered by
0
Answer:
as root 7 is coming continuously so put a bar on root 7 in way like our do in Normal numbers like 8 a coming unlimited times bar 8
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