Math, asked by lakshmi2238, 5 hours ago

find solutions of (x²-1)√2x-1=0​

Answers

Answered by vivekkumarsimri1
0

Answer:

(x²+1)√2×-1=0

(x²+1)-√2=0

x²+1=√2

x²=√2-1

x=√√2-1

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