Math, asked by satyam4648, 9 months ago

find som of 30+60+90+............+450​

Answers

Answered by jyotikhatkar1234
0

Answer:

30+60+90 = 180

450-180 = 270

270+180 = 450

30+ 60+90+180+270+450

Answered by spraveenbabu009
0

Answer:

3600

Step-by-step explanation:

First term(a)=30

difference between the terms(d)=30

last term(a↓n)=450

last term =a+(n-1)×d

450=30+(n-1)×30

450-30=(n-1)×30

420=(n-1)×30

420÷30=(n-1)

14=(n-1)

15=n....

sum of all terms(s↓n)=n÷2(first term+last term)

(s↓n)=15÷2[30+450]

(s↓n)=15÷2[480]

=7.5×480

→(s↓n)=3600

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