find som of 30+60+90+............+450
Answers
Answered by
0
Answer:
30+60+90 = 180
450-180 = 270
270+180 = 450
30+ 60+90+180+270+450
Answered by
0
Answer:
3600
Step-by-step explanation:
First term(a)=30
difference between the terms(d)=30
last term(a↓n)=450
last term =a+(n-1)×d
450=30+(n-1)×30
450-30=(n-1)×30
420=(n-1)×30
420÷30=(n-1)
14=(n-1)
15=n....
sum of all terms(s↓n)=n÷2(first term+last term)
(s↓n)=15÷2[30+450]
(s↓n)=15÷2[480]
=7.5×480
→(s↓n)=3600
Similar questions
Math,
4 months ago
Business Studies,
4 months ago
English,
4 months ago
World Languages,
9 months ago
Math,
9 months ago
Social Sciences,
11 months ago
India Languages,
11 months ago