Math, asked by suneetasuneeta9075, 4 months ago

Find SP or CP in the following problems: (a) CP = 700 , Profit = 12%
(b) SP = 1350, Loss = 10%​

Answers

Answered by ruchikumarinutan
0

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Answered by Anonymous
1

GiveN:-

  • (a) CP = 700 , Profit = 12%
  • (b) SP = 1350, Loss = 10%

To FinD:-

Find SP or CP in the following problems.

SolutioN:-

  • (a) CP = 700 , Profit = 12%
  • Here we have to find the SP.

We know that,

\large{\green{\underline{\boxed{\bf{SP=\left(1+\dfrac{Profit\%}{100}\right)\times\:CP}}}}}

where,

  • SP = ?
  • CP = Rs.700
  • Profit = 12%

Putting the values,

\large\implies{\sf{SP=\left(1+\dfrac{12\%}{100}\right)\times\:700}}

\large\implies{\sf{SP=\left(1+\dfrac{\cancel{12}}{\cancel{100}}\right)\times\:700}}

\large\implies{\sf{SP=\left(1+\dfrac{3}{25}\right)\times\:700}}

\large\implies{\sf{SP=\left(\dfrac{25+3}{25}\right)\times\:700}}

\large\implies{\sf{SP=\left(\dfrac{28}{25}\right)\times\:700}}

\large\implies{\sf{SP=\dfrac{28}{\cancel{25}}\times\:\cancel{700}}}

\large\implies{\sf{SP=28\times\:28}}

\large\therefore\boxed{\bf{SP=Rs.784.}}

VerificatioN:-

We know that,

\large{\green{\underline{\boxed{\bf{Profit=SP-CP}}}}}

where,

  • SP = Rs.784
  • CP = Rs.700

Putting the values,

\large\implies{\sf{Profit=Rs.(784-700)}}

\large\therefore\boxed{\bf{Profit=Rs.84.}}

Now,

\large{\green{\underline{\boxed{\bf{Profit\%=\dfrac{Profit}{CP}\times100}}}}}

where,

  • Profit = Rs.84
  • CP = Rs.700
  • Profit% = 12%

Putting the values,

\large\implies{\sf{12\%=\dfrac{84}{700}\times100}}

\large\implies{\sf{12\%=\dfrac{84}{7\cancel{00}}\times1\cancel{00}}}

\large\implies{\sf{12\%=\dfrac{\cancel{84}}{\cancel{7}}}}

\large\implies{\sf{12\%=12\%}}

\large\therefore\boxed{\bf{LHS=RHS.}}

  • Hence verified.

The Selling Price is Rs.784.

______________________________

  • (b) SP = 1350 , Profit = 10%
  • Here we have to find the CP.

We know that,

\large{\green{\underline{\boxed{\bf{SP=\left(1-\dfrac{Loss\%}{100}\right)\times\:CP}}}}}

where,

  • CP = ?
  • SP = Rs.1350
  • Loss = 10%

Putting the values,

\large\implies{\sf{1350=\left(1-\dfrac{10\%}{100}\right)\times\:CP}}

\large\implies{\sf{1350=\left(1-\dfrac{\cancel{10}}{\cancel{100}}\right)\times\:CP}}

\large\implies{\sf{1350=\left(1-\dfrac{1}{10}\right)\times\:CP}}

\large\implies{\sf{1350=\left(\dfrac{10-1}{10}\right)\times\:CP}}

\large\implies{\sf{1350=\left(\dfrac{9}{10}\right)\times\:CP}}

\large\implies{\sf{\dfrac{1350\times10}{9}=CP}}

\large\implies{\sf{\dfrac{\cancel{1350}\times10}{\cancel{9}}=CP}}

\large\implies{\sf{150\times10=CP}}

\large\therefore\boxed{\bf{CP=Rs.1500.}}

VerificatioN:-

We know that,

\large{\green{\underline{\boxed{\bf{Loss=CP-SP}}}}}

where,

  • CP = Rs.1500
  • SP = Rs.1350

Putting the values,

\large\implies{\sf{Profit=Rs.(1500-1350)}}

\large\therefore\boxed{\bf{Profit=Rs.150.}}

Now,

\large{\green{\underline{\boxed{\bf{Loss\%=\dfrac{Loss}{CP}\times100}}}}}

where,

  • Loss = Rs.150
  • CP = Rs.1500
  • Loss% = 10%

Putting the values,

\large\implies{\sf{10\%=\dfrac{150}{1500}\times100}}

\large\implies{\sf{10\%=\dfrac{150}{15\cancel{00}}\times1\cancel{00}}}

\large\implies{\sf{10\%=\dfrac{\cancel{150}}{\cancel{15}}}}

\large\implies{\sf{10\%=10\%}}

\large\therefore\boxed{\bf{LHS=RHS.}}

  • Hence verified.

The Cost Price is Rs.1500.

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