Math, asked by samarmalhotra, 9 months ago

find sq.rooot of --- a²-1+ 2a √-1​

Answers

Answered by jaidansari248
1

Answer:

 \sqrt{ {a}^{2} - 1 + 2a \sqrt{ - 1}  }  \\ we \: know \: that \:  \sqrt{ - 1}  = i \\  =  \sqrt{a {}^{2} +  {i}^{2}   + 2ai}  \\  =  \sqrt{ {(a + i)}^{2} }  \\  = a + i = a +  \sqrt{ - 1}

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