Question

find sq.rooot of --- a²-1+ 2a √-1​

Answer 1

Answer:

$\sqrt{ {a}^{2} - 1 + 2a \sqrt{ - 1} } \\ we \: know \: that \: \sqrt{ - 1} = i \\ = \sqrt{a {}^{2} + {i}^{2} + 2ai} \\ = \sqrt{ {(a + i)}^{2} } \\ = a + i = a + \sqrt{ - 1}$