Question

Find square of 41 by using Upsutra Anurupyena.​

Answer 1

Answer:

${41}^{2} \\ = (40 + 1) {}^{2} \\ = {40}^{2} + 1 {}^{2} + 2 \times 40 \times 1 \\ = 1600 + 1 + 80 \\ = 1681$