Question

Find square of : (7x^3+1/7y^3)

Answer 1

49x^9+1/343y^9 + 2x^3y^3

Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...

${( \frac{7 {x}^{3} + 1}{7 {y}^{3} }) }^{2} \\ = \frac{ {(7 {x}^{3} + 1) }^{2} }{ {(7 {y}^{3} )}^{2} } \\ = \frac{ {(7 {x}^{3} )}^{2} + 2 \times 7 {x}^{3} \times 1 + {1}^{2} }{49 {y}^{6} } \\ = \frac{49 {x}^{6} + 14 {x}^{3} + 1}{49 {y}^{6} }$
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