Question

find square root by repeated sudtraction method 256​

Answer 1

Step-by-step explanation:

Step 1: 256 - 1 = 255

/* Subtracting of first odd number */

Step 2: 255 - 3 = 252

/* Subtracting of second odd number */

Step 3: 252 - 5 = 247

/* Subtracting of Third odd number */

Step 4: 247 - 7 = 240

Step 5: 240 - 9 = 231

Step 6: 231 - 11 = 220

Step 7: 220 - 13 = 207

Step 8: 207 - 15 = 192

Step 9: 192 - 17 = 175

Step 10: 175 - 19 = 156

Step 11: 156 - 21= 135

Step 12: 135 - 23 = 112

Step 13: 112 - 25 = 87

Step 14: 87 - 27 = 60

Step 15: 60 - 29 = 31

Step 16: 31 - 31 = 0

From 256,we have subtracted 16 successive odd numbers starting from 1 and obtained zero (0) at 16 th step

Answer 2

Answer:

i) 256-1=255

ii) 255-3=252

iii)252-5=247

iv)247-7=240

v)240-9=231

vi)231-11=220

vii)220-13=207

viii)207-15=192

ix)192-17=175

x)175-19=156

xi)156-21=135

xii)135-23=112

xiii)112-25=87

xiv)87-27=60

xv)60-29=31

xvi)31-31=0

it takes 16 steps

√256=16