Music, asked by narayanaganji71, 9 months ago

find square root for the complex number - 5 + 12i​

Answers

Answered by khushi7190
4

Answer:

5 – 12i = x2 + 2ixy +(iy)2 = x2 – y2 + 2xyi. => x = ± 3. => y = ± 2. Therefore, √(5 – 12i) = 3 + 2i or, 3 – 2i or, – 3 + 2i or, – 3 – 2i

Answered by tennetiraj86
6

Explanation:

Given complex number = 5+12i

The square root of 5+12i is (5+12i)

Let (5+12i) = a+ib

On squaring both sides then

=>[(5+12i)]²=(a+ib)²

=>5+12i=+(ib)²+2(a)(ib)

=>5+12i=-b²+2abi

(=-1)

=>5+12i=(a²-)+(2ab)i

On comparing both sides then

=>-b²=5 and 2ab=12=>ab=12/2=6

by putting a=3; b=2 then

3²-2²=9-4=5

ab=(3)(2)=6

therefore , a=3 and b=2

now √(5+12i) = a+ib

=>√(5+12i) = 3+2i

and also it is true for a=-3 and b=-2

so, √(5+12i) = 3-2i

√(5+12i) = 3±2i

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