Find square root of 9-4 root 5
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1
Answer:
9−4
5
=4+5−4
5
=2
2
+(
5
)
2
−(2×2×
5
)
=(2−
5
)
2
∴
9−4
5
=2−
5
OR
\begin{lgathered}9 - 4\sqrt{5} \\ \\ = 4 + 5 - 4\sqrt{5} \\ \\ = (- 2)^2 + (\sqrt{5})^2 + (2 \times - 2 \times \sqrt{5}) \\ \\ = (- 2 + \sqrt{5})^2 \\ \\ = (\sqrt{5} - 2)^2 \\ \\ \\ \therefore \sqrt{9 - 4\sqrt{5}} = \sqrt{5} - 2\end{lgathered}
9−4
5
=4+5−4
5
=(−2)
2
+(
5
)
2
+(2×−2×
5
)
=(−2+
5
)
2
=(
5
−2)
2
∴
9−4
5
=
5
−2
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