Question

Find square root of the following decimal number. a 6.0516 step by step​

Answer 1

Answer:

2.46

Step-by-step explanation:

2.46 is the answer while doing with long division method.

Answer 2

$\large\underline{\sf{Solution-}}$

Given number is

$\red{\rm :\longmapsto\: \sqrt{6.0516} \: }$

Using Long Division Method, we have

$\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\:2.46 \:\:}}}\\ {\underline{\sf{2}}}& {\sf{\:\:6.0516 \:\:}} \\{\sf{}}& \underline{\sf{\:\:4 \:  \: \: \: \: \: \: \: \:}} \\ {\underline{\sf{44}}}& {\sf{\:\:205 \:  \:  \:}} \\{\sf{}}& \underline{\sf{\:\:176 \:  \: \:\:}} \\ {\underline{\sf{486}}}& {\sf{\:\: \: \: \: \: 2916  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \: \: \: 2916\:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  0\:\:}} {\sf{}}&{\sf{\:\:\:\:}}\end{array}\end{gathered}\end{gathered}\end{gathered}$

Hence,

$\red{\rm :\longmapsto\: \boxed{ \tt{ \: \sqrt{6.0516} \: } = 2.46 \: }}$

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More to know :-

1. The number of digits in square root of 2n digits is n.

2. The number of digits in square root of (2n + 1) digits in n + 1 digits.

3. Between square of two consecutive natural numbers n and n + 1, 2n natural number exist.

4. The sum of the first n odd natural number is n^2.