find square root of (x^2 +4x+4) (x^2 +6x+9)
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(x^2+4x+4)(x^2+6x+9)
on factorizing x^2+4x+4 and x^2+6x+9
we get (x+2)(x+2)(x+3)(x+3) ie
(x+2)^2(x+3)^2
square root of this is (x+2)(x+3) ie x^2+5x+6
on factorizing x^2+4x+4 and x^2+6x+9
we get (x+2)(x+2)(x+3)(x+3) ie
(x+2)^2(x+3)^2
square root of this is (x+2)(x+3) ie x^2+5x+6
Mirnalini6:
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First, solving the equations(x²+4x+4)(x²+6x+9)=> [x²+2(2x) +2²] [x²+2(3x) +3²] => [(x+2)²(x+3)²] Now, square root of (x+2)²(x+3)²=> √[(x+2)(x+3)] ²=> (x+2)(x+3)
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