Question

Find stationary point of the
function sinx siny sin(x+y)​

Answer 1

Answer: ∣x∣+∣y∣=1

Step-by-step explanation:

we know sin(x+y)=sinxcosy+cosxsiny

But it's given sin(x+y)=sinx+siny

∴ cosx=cosy=1⟹x=y=2nπ±0

Also x,y must satisfy ∣x∣+∣y∣=1

Therefore there is no common pairs of (x,y) which satisfies sin(x+y)=sinx+siny and ∣x∣+∣y∣=1

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