Question

find such a number which when multiplied by itself the product we get is equal to the product of all divisors of 27.

a. 529
b. 27
c. 9
d. 18​

Answer 1

Answer:

a. 14283

b. 729

c. 243

d. 486

Step-by-step explanation:

a) 529 ÷ y = 27

y = 529 × 27

y= 14,283

14, 283 when divided by 529 = 27

b) 27 ÷ x = 27

x = 27 × 27

x= 729

729 when divided by 27 = 27

c) 9 ÷ z = 27

z= 27×9

z = 243

243 when divided by 9 = 27

d) 18÷ k= 27

k= 27×18

k= 486

486 when divided by 18= 27

Answer 2

Answer:

don't know I came to see answer